[백준] 1002번 터렛 (파이썬)

1002번: 터렛

 

코드

import math

def solution(li):
    answer_li = []
    for case in li:
        x1, y1, r1 = case[0], case[1], case[2]
        x2, y2, r2 = case[3], case[4], case[5]

        dist = math.sqrt((x1 - x2) ** 2 + (y1 - y2) ** 2)
        
        if x1 == x2 and y1 == y2 and r1 == r2:
            answer_li.append(-1)
        elif dist > r1+r2:
            answer_li.append(0)
        elif dist == r1+r2:
            answer_li.append(1)
        else:
            if dist+r2 < r1 or dist+r1 < r2:
                answer_li.append(0)
            elif dist+r2 == r1 or dist+r1 == r2:
                answer_li.append(1)
            else: 
                answer_li.append(2)
        
    for i in answer_li:
        print(i)


n = int(input())
li = []
for _ in range(n):
    input_li = list(map(int, input().split(" ")))
    li.append(input_li)

solution(li)